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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Aug 2007 10:54:34 IST
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If G is the centroid of triangle ABC &O is any other point ,prove that OA2 +OB2+OC2=GA2+GB2+GC2+3GO2. PLEASE HELP...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Aug 2007 13:31:45 IST
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can u provide a diagram? and is the triangle equilateral or not mentioned. and is point O lying on the triangle? or inside or outside?
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Aug 2007 17:49:49 IST
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nothing else has been mentioned in the question..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Aug 2007 22:21:32 IST
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Try Using Apolonius Principle If I Am Not Wrong.......This is a sum from the 2nd exercise of Loney...am i right ?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Aug 2007 20:16:47 IST
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We can also prove this by analytical geometry. Assume the vertices triangle be (x,y);(h,k);(a,b); and take O as any value like (l,m). Find 0A,0B and OC using distance formula and substitute in LHS. OR Find GA,GB,GC and OG and substitute the values in RHS. You will get the answer.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Aug 2007 20:32:47 IST
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its not so easy that way..im thinking of a method
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---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 16:26:49 IST
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A(x1,y1),B(x2,y2),C(x3,y3) n O (h,k) G(sigma x1/3. y1/3) OA^2 + OB^2 + OC^2 = (h - x1)^2 + (k - y1)^2 + .... (x1^2 + y1^2) + (x2^2 + y2^2) + (x3^2 + y3^2) + 3(h^2 + k^2) -2h(x1 + x2 + x3) - 2k(y1 + y2 + y3) GA^2 + GB^2 + gc^2 + 3GO^2 - 0 - 0 {GO^@ = (H - O )^2 + (K - O)^2}
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 21:13:31 IST
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hey i think this is a 3d question i have the soln in 3 d let the vector OA=a and the vector OB=b and the vector OC=c.centroid of the triangle is given by OG=a+b+c/3 then (OA)2+(OB)2+(OC)2=a2+b2+c2 then GA2=((b+c-2a)/3)2 ,GB2=((a+c-2b)/3)2,GC2=((b+a-2c)/3)2 then GA2+GB2+GC2+3OG2=9a2+9b2+9c2/9 this is equal to OA2+OB2+OC2
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