See buddy.......

represents a pair of straight lines.....
factorizing it and getting the two lines.......as,...........
)(x%20%2B%20y(2%20-%20\sqrt{3}))%20=%200)
so the two lines are.........
%20=%200\\x%2By(2-\sqrt{3})%20=%200)
and the third one is given........
x + y =1..........
solve these three equations.....get the three vertices of the triangle formed by them.......
and then use this formula for getting the coordinates of the centroid,,,,,,,,,
%20=%20(\frac{{x}_{1}%2B{x}_{2}%2B{x}_{3}}{3},\frac{{y}_{1}%2B{y}_{2}%2B{y}_{3}}{3}))
hope u can do the calcs........
cheers........