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Analytical Geometry

Blazing goIITian

Joined:	5 Nov 2007
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30 Nov 2007 11:17:09 IST

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544

Straight lines-easy level

None

A line is such that its segment btw the lines 5x-y+4=0 and 3x+4y-4=0 is bisected at the point(1,5).Obtain its equation.

Its easy,but i'm stuck.

Rates assured.

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Comments (6)

harman ghuman

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Joined: 22 Nov 2007

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30 Nov 2007 11:36:15 IST

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is it 13x-2y-3=0

Akshay Pamnani

Blazing goIITian

Joined: 27 Nov 2007

Posts: 470

30 Nov 2007 12:29:32 IST

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Here's the method

Use parametric form to get X1 and X2 in terms of r and theta,then subs. in line equation as they lie on line,then find X2 and Y2 in form of r and theta,then subs. in second equation,solve for r and theta and get the equation,if u have a doubt then nudge me,

or plzz rate me

sowjanya gudipati

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30 Nov 2007 16:03:46 IST

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hey ghuman i m finding ur answer wrong because when we solve the given lines with ur answer line we get the point of intersection of the lines and when the midpoint is found out its not matching with the given midpoint.so do verify ur answer.

sowjanya gudipati

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Joined: 13 Oct 2007

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30 Nov 2007 16:25:26 IST

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i have one more method to solve this.that is

express the equation as 5x+4=y and let (x1,y1) be a point on the line then express y1=5x1+4

know let the point (x2,y2) be the point on the second line 3x+4y-4=0 then this gives y2=(4-3x2)/4

know take the midpoint between (x1,y1) and (x2,y2) and equalise it to (1,5)

x1+x2=2 and y1+y2=10

this gives x1=26/23, y1=222/23,x2=20/23 and y2=8/23

then find the equation connecting (x1,y1) and (x2,y2)

Learner .

Blazing goIITian

Joined: 5 Nov 2007

Posts: 507

1 Dec 2007 11:31:41 IST

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I'm really sorry-havent learnt parametric form...

@sowjanya-I tried that,but didnt get it.I'll try again.

Thanks everyone!!

Learner .

Blazing goIITian

Joined: 5 Nov 2007

Posts: 507

2 Dec 2007 09:54:37 IST

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107x-3y-92=0

This is what i got..

pl tell if its right or not!

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