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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2007 00:29:08 IST
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If the distance of any pt(x,y) from the origin is defined as d(x,y)=MAX{ IxI,IyI} then the locus of the point (x,y) where d(x,y)=1 is 1) A circle 2) A square 3) A triangle 4) A rectangle
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16 Mar 2007 09:00:35 IST
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Its a square
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Think different .........................think apple
ALBERT EINSTEIN |
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16 Mar 2007 13:13:31 IST
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by the definition of d.... there are four pts on the coordinate axis which satisfy this condition....(1,0 (-1,0) (0,1) (0,-1)
The only figures which can pass thru these pts are ... circle,square nd rectangle....
in a circle the distance of the pt from the center is alyays one....hence this is ruled out...
in a rectangle there is a point where the the distance from the origin becomes sqrt(2) (vertices).... hence it is ruled out...
hence by elemination.. the only figure left is square
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16 Mar 2007 16:08:38 IST
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a circle
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sachin |
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16 Mar 2007 16:21:10 IST
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i am confused by the 1st condition but the second one means it has to a be a circle
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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MOST PROBABLY IT IS SQUARE
bcoz
mod(x).mod(y)=1 then
1.x=1,y=1
2.x=-1,y=1
3.x=-1,y=-1
4.x=1,y=-1
these four points form a square
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DO NOT FOLLOW MY WAY.
IT'S TOO DANGER. |
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16 Mar 2007 18:50:19 IST
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ITS A SQUARE
WITH AREA 4 SQ UNITS
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16 Mar 2007 18:53:13 IST
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its a square
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vision for iit never ends........ |
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16 Mar 2007 20:59:26 IST
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since d(x,y)=1 and max{mod x, mody}=d(x,y) we havemod x=1 i.e x=+1 or -1 similarlly y=+1 or -1.so they are strait lines which form a square
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