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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:14:28 IST
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Q. a metre scale made of steel is calibrated at 200C to give correct readin. Find d distance b/n 50 cm mark and 51 cm mark if d scale is used at 100C. Coefficient of linear expansion of steel is 1.1 *10-5/0C.
ans is1.00011 cm.
if u get dis ans plz explain me d logic.
i got .999. as it should contract wen temp decreases.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:23:53 IST
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i remebber the sum.
the ans ans is1.00011 cm.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:27:04 IST
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the logic is :
consider 2 pegs b/w 50 and 51 cm
At 20 degree , it gives correct distance 1 cm.
at 10 degree , the scale is reduced so the dist. b/w the pegs if measured will be greater than 1.
Actually Bipin Bhaiya ( expert ) helped me.
It was long ago , april last yr.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:36:08 IST
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edited.
Yes. I m right.
It is Q. 11 of page 12 vol II of hcv. ( just checked )
I made the same mistake which u made now.
Remember the distance between 2 columns ( say ) at 50 cm and 51 cm is fixed. U r not shifting the columns.
Now when measured with a scale at 20 degree , this distance comes out as 1 cm.
so when measured with a scale at 10 degree , the scale i, e measuring instrument , is reduced.
This distance then comes out as 1.00011 cm by this faulty scale.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:44:07 IST
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listen when u decrease the temperature, the scale contracts meaning the reading will be more.
if it was showing a lenght of 5 b4 now it shuld show more than that..
got the logic?.. so now apply Length(read)=lenght(actual) *(i+alpha *change in temp)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:45:59 IST
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tell me if u still didnt get i'll solve it for u
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 23:59:48 IST
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This Q reminds me my journey thro Verma which is yet to be finished.
It was april 2007.
Unlike others, I started with Heat, expansion, calorimetry.
I first thought there is some mistake in the result. But others say, it is a no - mistake book. So I tried here and there. Also posted in goiit.
This Q reminds me the memory and thanks for that.
P.S. Don't know, whether I should hav said it here.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jul 2008 20:10:48 IST
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I agree with zark...
As the scale contracts...the pegs also comes closer....so if we r measuring any rod with dat same scale at 10C....we get an increased length shown by the faulty scale.
actually first even i made d same mistake but got it later...!!!
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Don't be a victim of circumstances
Be the master of circumstances!!! |
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