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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 19:50:52 IST
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for a mixture of n1 moles of a monoatomic gas and n2 moles of a diatomic gas has its Cp/Cv = 1.5 find the ratio n1/n2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 20:26:42 IST
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We have
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 20:47:15 IST
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is the ans 5/8
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2007 12:08:35 IST
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On mixing the two gases (n 1+n 2)Cv mix T = n 1Cv gas1 T + n 2Cv gas2 T----(i) now it is given that the mix =3/2 we have Cv mix=R/  -1 Cvmix=2R(on putting gamma=3/2) also, Cvgas1=3R/2 and Cvgas2=5R/2 on substituting all these values in equation 1 we get (n1+n2)2R=n1(3R/2) + n2(5R/2) n2/2=n1/2 n1/n2=1 thanks
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2007 12:35:15 IST
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Cp={5R/2(n1)+7R/2(n2)}/{n1+n2} Cv={3R/2(n1)+5R/2(n2)}/{n1+n2} &Cp/Cv=1.5 => n1/n2=1 i think its absolutely right.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Apr 2007 15:10:23 IST
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him26.89, I would like to correct you, your answer is wrong... Ans.:-n1/n2=3/5 Soln.:-  =C pn 1+C p'n2/n 1+n 2 1.5=1.66*n1+1.4n2/n1+n2 1.5n1+1.5n2=1.66*n1+1.4n2 therefore, 1/6n1=1/10n2 therefore, n1/n2=3/5... Hope it is correct....... Please rate for my efforts.... Thanx....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Apr 2007 15:12:32 IST
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neeleshv, your formula is absolutely incorrect...
Hope you correct it, I have written it down....
But, btw atleast you gave it a try......
Hope you rate me........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2007 12:11:36 IST
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hi chirag you have made a mistake you have taken Cp=1.66 which is wrong and the formula given by neeleshv is correct.
check my solution
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2007 21:30:10 IST
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Joyfrancis you are absolutely wrong, Cp or Cv cannot be equal to 1.66, since it is in terms of R... Neelshv's formula is also wrong.... I have corrected my answer, now it is absolutely correct... Initially I had made a mistake by not considering Cv in the denominator... My formula is absolutely correct.. Hope you check it in H. C. Verma.... Ans.:-n1/n2=1/2 Soln.:- mix=C pn 1+C p'n 2/C vn 1+C v'n 2 For monoatomic gas, Cp=2.5R, Cv=1.5R For Diatomic gas, Cp'=3.5R, Cv'=2.5R 1.5=2.5R*n1+3.5Rn2/1.5Rn1+2.5R' 2 4.5n1+7.5n2=5*n1+7n2 therefore, 0.5n1=0.5n2 therefore, n1/n2=1/1........ Please rate for my efforts.... Thanx....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2007 21:59:10 IST
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so can't we use the formula mix=( 1n1 + 2n2)/(n1+n2)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2007 23:23:21 IST
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hey........ Did you get the formula by just using cp=cp1*n1+cp2*........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 09:42:04 IST
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hey chirag how did you get this gamma=Cpn1+Cp'n2/n1+n2...can you please explain
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 10:41:24 IST
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joyfrancis is absolutely correct... nd the formula given by neeleshv is also correct... joyfrancis has given the proof... chirag how have u got that formula... pls enlighten us too....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 13:37:40 IST
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Anjishnu, mix=( 1n1 + 2n2)/(n1+n2), this formula is absolutely wrong..... correct formula is , mix=C pn 1+C p'n 2/C vn 1+C v'n 2 Joyfrancis, initially, I had made a mistake by not considering Cv in the denominator.... Sorry, it' was my mistake, but i have posted the corrected soln already..... Magiclko,regarding the proof can you please refer H. C. Verma part II page 75 Solved example 10... I will not be able to write the whole proof due to typing constraints....Please co-operate... If still you are unable to get , I will help you..... Thanks.....
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