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Thermal Physics

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Joined:	12 Nov 2007
Post:	211

19 Jan 2008 11:23:44 IST

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226

Kinetic Theory of Gases

None

The diagram shows a cylindrical tube with adiabatic walls and fitted with a diathermic separator. The separator can be slid in the tube by an external mechanism. An ideal gas is injected in the two sides at equal pressures and equal temperatures. The separator remains in equilibrium at the middle. It is now slid to a position where it divides the tube in the ratio 1:3. Find the ratio of the pressures in the two parts of the vessel.

Ans: 3:1

PS: See the question may be a long one but if you read it patiently you will surely be able to crack it.

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NITESH BASKARAN

Blazing goIITian

Joined: 29 Sep 2007

Posts: 487

19 Jan 2008 13:28:55 IST

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assuming that initially there is no transfer of heat between the two parts
let P be the initial pressure and P(a) and P(b) be the pressure in the two parts after compression
the volume are 1/4 V and 3/4 V where V is the volume of the container
using PV=constant you get
P(a)=4 P/2
P(b) = 4/3 P/2
P(a)/P(b)=3 : 1

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