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[Post New]3 Mar 2007 21:15:59 IST
    Subject: KTG
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tejasvi2389 (33)

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Consider a sample of oxygen at 300K Find avg time(in hr)taken by a molecule to travel a distance equal to diamater of earth
please xplain
    
[Post New]4 Mar 2007 14:49:33 IST
    Subject: Re:KTG
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chirag (384)

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Ans:- 5.61 Hours
 
Soln:-
 
v(avg)=sqrt(8RT/piM)
sustituting the values, we get,
v(avg)=630m/s
diamter of earth=12732km=12732000m
 
therfore, time=12732000/(630*60*60)=5.61 hours


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[Post New]5 Mar 2007 09:37:37 IST
    Subject: KTG
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tejasvi2389 (33)

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Ans is 8hrs explain how this is from HC verma
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[Post New]5 Mar 2007 09:44:53 IST
    Subject: KTG
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nishant (350)

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hello chirag,i guess the average velocity value which u have found out is wrong...otherwise,rest of the soln. is correct..do check it once more.
never give up in life.keep trying till you succeed.don't forget to rate my answers if u find them to be correct as it will only boost my confidence....
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[Post New]8 Mar 2007 00:33:28 IST
    Subject: KTG
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krishna.gopal (2397)

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Good work Nishant and nice try chirag. The average velocity is about 444m/s which gives time =8hrs
Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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[Post New]3 Apr 2007 01:56:54 IST
    Subject: Re:KTG
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chirag (384)

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I have checked my soln, still I am getting 630m/s.
 
Pl tell me how did you get 444m/s


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