IIT JEE , AIEEE Forum - Physics , Thermal Physics

balesh

container A has a sample of monoatomic ideal gas,while container B has sample of diatomic ideal gas. the 2 gases start with the same initial temp. ,volm.,prr., and no. of moles of molecules. each gas now undergoes a reversible adiabatic process that cuts the pressire in half. which sample of gas is now at the higher temp.

mukeshpal.pal

A gas has higher temperature.

krishna.gopal

For adiabatic process P^1+1//Tis constant

So for any gas T final = T initial*(0.5)^^1+1/

Gamma for mono atomic gas is 5/3 and for diatomic gas is 7/4

As initial temperature of both gases is same so for final temperature of both gases are

T_mono/T_di=(0.5)^8/5/(0.5)^11/7=0.5^(1/35) So T_mono <T_di

So B will have higher temp

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