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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 May 2008 12:09:10 IST
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How many times the molecules of a diatomic gas is expanded to reduce the root mean square velociy of the molecules to 20/30 of initial value
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5 May 2008 13:21:00 IST
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SOMEBODY!
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5 May 2008 17:30:37 IST
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From kinetic theory of gases v 've exp 4 rms speed as
Vrms=?3RT/M=?3PV/M
Dividing eqns 4 initial & final conditions
Vrms1 /Vrms2 =?V1/V2
Substing and squaring
(3/2)^2 = V1/ V2
or V2=4/9 V1
Thus molecules 've 2 b expanded 4/9 times its original volume.Atomicity of gas doesn't matter
Hope its ALLCLEAR!!!Bye...
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9 May 2008 21:41:21 IST
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Thanks a ton..but over here 3RT/M=3PV/M' , M'=NM.
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10 May 2008 22:44:02 IST
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Why an M'?
Pl inspect the questn once again..
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13 May 2008 22:38:22 IST
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Okay...Now c, actually KGT saya
P=1/3*density*mean square velocity
When v substitute M/V for density,
P=1/3*Mv^2/V
Note tat if v substitute 4 1 mol of substance,M bcoms molar mass
&using ideal gas eqn PV=RT ,v get
v=3RT/M
Ur confusion is bcoz u don't see its 4 1 mol tat v convert da basic eqn...v dont subst density with a simple mass/volume...but molar mass..
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