IIT JEE , AIEEE Forum - Physics , Thermal Physics

joyfrancis

if a gas gas undergoes a process such that P=kV, what is the value of molar heat capacity of the gas?

priyesh

how can pressure be directly proportional to volume.

if pressure increases volume has to decrease & vice versa.

rushali

hi see take initial and final vol as Vi and Vf , as W=PdV , put P=kV and integrate to get W . U = PfVf - PiVi /

- 1 , so get U in terms of

and then find

T by using PV=nRT ie get

T in terms of R and yes Q = U +W then you know C=Q/change in T so this is how you get C . if i m clear i wait for a salute

vish0001

techinically speaking, i think it's not possible that a gas undergoes a process like p = kv.

the Cv constant simply applies for all processes performed at constant volume

=> for the process P= KV , to calulate Cv , V= constant or P = constant

=> Cv = 1 + 2/f { f is degrees of freedom }

DON007

vishal is right................the process can not exist...............

but u dont worry .

MAIN HOON NAA........( KIDDING)

look ,

C(4 THIS PROCESS)= R/ (

- 1) + R/2

I M SURE ABT IT...................... FREEZE IT.........

bumba

Cp=0

joyfrancis

I got it...thanks

prashant3670

the given process is possible for ideal gas, but the nature of the gas has to be known to calculate the molar heat capacity.

assuming the gas to be monoatomic, the ans should be 2R. similar question was asked ( in fact the same) in IITJEE 2006, but here the nature of gas monoatomic was given.

clear?

vish0001

can u explain hw u did it >>?? meanwhile, i scanned the question paper and got no such quest, !

chirag

If the gas is monoatomic, then answer is 2R, if diatomic then 3R....

formula:- c=R/(cp/cv)-1- R/n-1, where n is the co-efficient of V on the question....

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