physics chemistry maths science forums
become expert I help I sign up I login
refer a friend - earn nickels!!   
 advanced
 
Home
Ask & Discuss Questions
Study Material
Experts Zone
Hang Out!

Ask & Discuss Questions with Community & Experts

Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board community Community Discussion Question: somebody solve it....
Forum Index -> Thermal Physics like the article? email it to a friend.  
Author Message
abhishekneha (0)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [0 rates]

abhishekneha's Avatar

total posts: 25    
offline Offline
PLS DONT NEGLECT IT THINKING IT TO BE A LONG QUESTION....
 
1)an ideal gas is trapped btn a mercury column and closed end of a narrow vertical tube of uniform base containing the column. the upper end of the tube is open to the atmosphere. the atmospheric pressure equals 76 cm of mercury.the length of the mercury column and the trapped air column are 20 cm and 43cm respectively. what will be the length of the air column when the tube is tilted slowly in a vertical plane through an angle of 60 degrees?
assume the temperature to remain constant?
ANS:48cm.
 
2)a vertical cylinder of height 100cm contains air at a constant temperature. the top is closed by a frictionless light piston. the atmospheric pressure equals to 75 cm of mercury. mercury is slowly poured over the piston. find the max ht of the mercury column that can b put on the piston?
ANS:25cm
    
madman (239)

Blazing goIITian

Olaaa!! Perrrfect answer. 33  [70 rates]

madman's Avatar

total posts: 486    
offline Offline
2.
since temperature remains constant
PV=constant
initial pressure = 75 cm Hg
initial volume = 100A
A-area
let the length of cylinder containing gas be h
then final volume = Ah
final pressure = ( 75 + 100-h)
where 100-h is the height occupied by mercury
75 x 100 = h(175-h)
solve the quadratic
the two solutions are h= 100 and h = 75
h= 100 is not possible
therefore h=75
height of mercury = 100-75 = 25cm

science-
the most fundamental
the most eternal
 this reply: 7 points  (with Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Thermal Physics
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya