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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Thermodynamics challenge
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elastiboysai (2327)

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A simple one
Thermo challenge
A copper and a tungsten plate having a thickness of 2 mm each are riveted together at 00C 2 form a bimetallic strip
Find the average radius of curvature of this plate at 2000C
The coefficients of linear expansion for copper and tungsten are
1.7*10-5 and.4*10-5  K-1 respectively

edited:10-5K-1 not 10-1K-1
    
computer001 (1847)

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edit

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computer001 (1847)

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have u missed out the initial length??

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elastiboysai (2327)

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nope
not required (though im not supposed 2 mention it)
This shud give u a clue
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computer001 (1847)

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edit
sorry i did complete crap...:

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computer001 (1847)

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edited:
din c u chng value


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Mathsgirl (0)

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Isn't it 19 units
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computer001 (1847)

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r@=l(1+a2T)
(r+4)@=l(1+a1T)


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computer001 (1847)

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870mm
P.S:872.5217402

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elastiboysai (2327)

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Hint:
For the formula, u gotta use mean radius
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NAKEWL (38)

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0.86m
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karthik2007 (3399)

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Here's my attempt:

When they expand together, they form something like a part of a circle, though not exactly a circle. Let the angle subtended at the center of this so called circle be @ radians.

Now, for copper, we have l1 = l(1+at)

For tungsten, we have l2 = l(1+bt) where the terms on LHS are the lengths after expansion. Hence, we get, from simple trigonometry,

l1 = (R+d)@
l2 = (R-d)@

Hence, subtracting, we get :

2d@ = l(a-b)t

But @ = l/R (This is where my mind is full of doubts... I've taken l almost equal to l1 or l2... :(   Probably this might screw my solution)

Hence, using this, we get:

2d/R = (a-b)t

where 2d = 2mm

Hence, on putting values, we get  R  to be about 74 cms.

edit - I did the calculations using a calculator now, and the exact ans is 76.8797cm




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karthik2007 (3399)

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okay... ans is right :)

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computer001 (1847)

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question is find radius
n 4 u tht turns out to be 434mm
but ans is in 700s

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computer001 (1847)

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karthik expain:
acc 2 u :
2d/R=2.3*(10^-5)*200
=>1/R=2.3*10^-3
so R=1000/2.3
how is tht 770mm??

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