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Ask iit jee aieee pet cbse icse state board experts Expert Question: Thermodyanamics 1st law
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rhd92781 (686)

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An ideal monoatomic gas is confined by a spring loaded massless piston of cross section 8*10-3 m2. Initially the gas is at 300 K and occupies a volume of 2.4*10-3 m3 and the spring is in its relaxed state. The gas is heated by an electric heater until the piston moves out slowly without friction by 0.1 m. Calculate:
 
(a) The final temperature of the gas and
(b) the heat supplied by the heater.
 
The force constant of the spring is 800 N/m, atm pressure is 1.0 * 105 N/m2. The cylinder and the piston are thermally insulated.

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rhd92781 (686)

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experts please help

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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nishantsingh89 (975)

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wait commited an error , solving again

The heights which great men reached and kept, Were not attained by sudden flight, They, whilst their companions slept, Were toiling upwards in the night....
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iitkgp_bipin (6144)

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Initially the pressure inside cylinder, P0 = 1.01x105 Pa, V0 = 2.4x10-3 and T0 = 300 K

Increase in volume = (area of cross-section).(height by which piston rises) = (8x10-3)(0.1) = 0.0008 m3
So, final volume, V = 0.008+0.0008 = 0.0088 m3

The spring is compressed by 0.1 m and hence it will exert a pressure of kx/A on piston.
So final pressure, P = (P0 + kx/A) = (1.01x105 + 800x0.1/8x10-3) = 1.11x105 Pa

Now apply  P0V0/T0 = PV/T

So you can calculate final temperature T from this.

Small work done by gas, dW = P.dV

dW = (P0 + kx/A).d(Ax) = A(P0 + kx/A).dx = (P0A + kx).dx

dQ = dU + dW

Integrate both sides :

Q = U + [ ][ ] dW

Q = nCvT + [0][0.1] (P0A + kx).dx

Now its simple carry out the integration and put the other values to find the heat supplied.


 

Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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rhd92781 (686)

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well i did the same thing but got answer different from the book's. probably d c pandey solved it wrongly

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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