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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 10:59:02 IST
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A and B are 2 heat engines. A operates with revervoir temp. 500K and 300K .B operates with revervoir temp. 600Kand 450K . WHICH IS MORE EFFICIENT AND HOW MUCH
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HI FOR A, T1=500K T2=300K EFFI.. = 1- T2/T1 =40 FOR B, EFFI.. = 25 HENCE A IS MORE EFFI... THEN B BY 15
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21 Feb 2007 01:52:35 IST
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efficiency for a = n*100=2/5*100=40%
efficiency for b = n*100;1/4*100=25%
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21 Feb 2007 18:45:41 IST
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man prabhuling how can a efficiency be ever greater than 1. yours is coming to be as 40!!!!! Second Law Of Thermodynamics VIOLATED!!!!!!
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Do I NeEd A SiGnAtUrE To PrOvE MySeLF!!! |
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21 Feb 2007 19:21:49 IST
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i agree with eshaan's law but eshaan he has expressed it as percentage...... so he's absolutely rite ma solute goes 2 him
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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21 Feb 2007 20:54:54 IST
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Hey ehsaan ! Prabhuling has done absolutely correct . You only saw the answer , not the method . 1-T2/T1 comes out to be 0.4 , but he has written the % . So , he is correct !
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Umang |
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25 Feb 2007 23:08:17 IST
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by using efficiency=1-t2/t1,we get
efficiency in A=0.4
and
in b,efficiency=0.25
thus,A has better efficiency than B.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
   
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
RATE ME FOR MY EFFORTS....... |
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