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Thermal Physics

Blazing goIITian

Joined:	12 Dec 2007
Post:	1249

18 Jan 2008 18:25:38 IST

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468

THERMODYNAMICS IN CO-ORDINATION WITH HYDRODYNAMICS - CREATION OF MY OWN

None

HERE IS A BEAUTIFUL QS. THERE ARE TWO CONTAINER OF SAME AREA OF CROSS SECTION AND ONE ABOVE THE OTHER THE ABOVE ONE CONTAINS AND IDEAL GAS AND LOWER CONTAINS A IDEAL , NON-VISCOUS AND PERFECTLY NON CONDUCTING FLUID .
THERE IS AN ORIFICE AT THE BOTTOM FROM WHICH THE FLUID IS FLOWING . ATMOSPHERIC PRESSURE IS P0 AND ADIABATIC EXPONENT IS
WALL ARE PERFECTLY NON HEAT CONDUCTING AND NO LEAKAGE IS THERE . THE CYLINDERS HAVE EQUAL HEIGHT L . FIND
1: THE VELOCITY OF THE OUT COMING WATER AS A FUNCTION HEIGHT OF WATER H
2: THE MINIMUM ANGULAR VELOCITY WITH WHICH THE CONTAINER SHOULD BE ROTATED SO THAT THE VELOCTIY GETS DOUBLED FOR THE SAME HEIGHT AS EARLIER
ANSWERS WIL BE POSTED BY NEXT WEEK...........FIGURE IS GIVEN

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bladeX -rise of a new sun

Blazing goIITian

Joined: 12 Dec 2007

Posts: 1249

20 Jan 2008 11:54:19 IST

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come on try................it's one the best qs i have found......................
go back to your basics......
5 days to answer
5 salutes assured................

abhishek sinha

Forum Expert

Joined: 18 Dec 2007

Posts: 926

20 Jan 2008 16:18:15 IST

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It is simple .

Use P V ^

= const to find P vs h

Next use Bernoullis eqn to find the velocity.

Make use of continuity eqn Av = const to find the reln between velocity of water level at the top and at the orifice .

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