Consider a lake of depth 1m.the temperature of the surrounding atmosphere is (-10⁰C) . the bottom of the lake is maintained at 4⁰C . find the maximum thickness ice that would form .

density of ice is 10^3 kg/m3

latent heat of fusion of ice is 3.36*10^5

Kice=1.7

Kwater=0.5

this is hc verma qstn 16 from heat transfer.

someone plzzz try...

someone plzzzzzzz try.

just a correction the given sum is sum no 15(and not 16) from hc

plz  plzz plzzz help me .i have already wasted about 1^_1/2 hrs behind this sum.plzzzz help...

Hints :

rate of heat entering the ice from bottom -rate of heat given out by ice to outside atmosphere = Latent heat *dm(ice )/dt

Now at maximum thickness , dm/dt =0

so RHS equals zero

From that relation x(max )can be found out .

Ans =8.5 m

sir, the ans given is 89cm.

i think ur ans is incorrect coz logically too sice the depth of the lake is 1m how can u have thickness of ice as 8.5m?

plzzz plzzz plzzz ,someone help!

just 1 reply that too in 36hrs