IIT JEE , AIEEE Forum - Chemistry , Inorganic Chemistry

Arjun

in applying valence bond theory to compounds like [NiCl₄]^-2and [NiCN₄]^2-

how do we know tat in nickel tetrachloride sp³ orbitals are filled and in nickel tetracyanide dsp²orbitals are filled?

plzzzzzzz help

chimanshu_007

COZ IN nickel tetrachloride cI IS A WEAK FEILD LIGAND SO IT WILL NOT PAIR THE ELECTRONS HENCE HYB IS SP3 BUT IN nickel tetracyanide CN IS A STRONG FEILD LIGAND HENCE IT WILL PAIR UP THE LEFT ELECTRONS HENCE HYB IS DSP2

Arjun

can u temme how to apply VBtheory to ne coordination compound given?
plzz help

madhuri_goteti

cynaide is a strong ligand so it pairs up the single electrons hence a emptyorbital is formed in the given 3d shell itself it is SP₃

chimanshu_007

there are 2 strong feild ligands basically in our syll. one is CN and other is CO

magiclko

the oxidation state of Ni in both the compounds is +2 thrfore electronic configuration of Ni+2 ion is 1s(2) 2s(2) 2p(6) 3s(2) 3p(6) 3d (8)

it will be something like shown in attached figure....

now in case of Cl(-), it is a weak field ligand, so cant do the pairing of the unpaired electrons, so the electrons frm the ligands will hav to go to the vacant s and p orbitals.. giving it a sp3 hybridisation

while on the other hand, CN(-) is a strng field ligand, so will get the unpaired electron paired up.... thus thr will be one d orbital will be vacant, hence the electrons frm the ligands will go to d, s and p orbitals, giving it a dsp2 hybridisation

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