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Inorganic Chemistry

Blazing goIITian

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27 Feb 2009 17:41:09 IST

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1. Methoxy ethane reacts with HI to give methyl iodide & ethanol & not ethyl iodide & methanol.

2. Tert butyl methyl ether reacts with HI to give methyl iodide & methanol & not methyl iodide & tert butyl alcohol.

3. Anisole undergoes electrophillic substitution at ortho and para position.

4. Boiling point of butan-1- ol is higher than tert butyl alcohol.

5. Alcohol, phenol and ether are soluble in water

6. Alcohol behaves as nucleophile as well as electrophile.

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tina

Blazing goIITian

Joined: 25 Oct 2008

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28 Feb 2009 10:38:52 IST

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Pls. reply...

sneha

Blazing goIITian

Joined: 17 Mar 2008

Posts: 1243

28 Feb 2009 10:52:33 IST

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5.actually only lower members of these are soluble due to H-bonding

2. I think it gives tert-Butyl iodide and methyl alcohol and not methyl iodide

3. it is because -OR group is ortho-para directing group. it is clear from its resonance structures.

4. in isomeric compounds, branching reduces surface area which lowers the strength of vanderwaals forces. this causes boiling point to decrease

6.refer ncert page no. 326 its clearly explained there

Feuer Zaber

Blazing goIITian

Joined: 12 Jul 2008

Posts: 310

28 Feb 2009 11:00:34 IST

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Read the ncert text properly.The mechanism is given on the 2nd page of ethers(ie,after williamson's ether synthesis).

3.The electrons on oxygen activate the ring at o & p postions.

4.Streric hindrance reduces the stability of tert.butyly alcohol.So,boiling point is lower,

6.read the text properly.Its there in the beggining of the rections of alcohols.The O-H bond cleaves when alcohols act as nucleophilsand R-O bond when it act as electrophile(ie,R-O^- and R⁺ are formed)

vignesh the cooler version of newton

Blazing goIITian

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28 Feb 2009 11:01:19 IST

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1st = it takes place thro Sn2 mechanism as the Sn1 products are unstable for both.. now, I- ion can attack the methyl part most easily as it is sterically less hindered.. hence, CH3I is formed along with C2H5OH as the major product..

2nd = this reaction will take place thro Sn1 mechanism as the tert-butyl carbocation is very very stable.. hence, tertbutyl Iodide is formed along with formation of methanol as the major product

3rd. = anisole has O-CH3 group which is good activating o,p directing group throug its +R effect.. hence, anisole undergoes electrophilic substitution at o,p positions..

4th = boiling point decreases with branching becoz with branching, effective surface area decreases and the compound tends to be more spherical.. hence, the van der waal forces are lower in tert-butylalcohol...hence, tert-butyl alcohol has lesser bp than n-butanol

5th - because of H-bonding..

6th = when C-O bond is broken, alcohol behaves as electrophile.. , but due to the presence of 2 lone pairs of electron in O atom, it behaves as nucleophile and here, O-H bond is broken..

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