IIT JEE , AIEEE Forum - Chemistry , Inorganic Chemistry

icy_2291

What is the hybridisation of N and B in the 1:1 complex of BF₃

NH₃

_{Reply with explanation please}

rik_mad

both are sp3 hybridized

anchal_1991

BF3 HAVE CONFIGURATION 1s2 2s2 2p1
so we have s orbital with 2 electrons and 1 electron in p orbital in ground state in 2nd shell.in excited state s orbital will have 1 electron&p orbital will have 2 electrons.now 1 flourine needs 1 electron to complete its octet.
so now as B HAVE 3 valence electrons in s and p orbitals.so 3 F WILL TAKE THESE 3 ELECTRONS TO have its octet complete and B will have its 1 s orbital overlap with 1 F AND 2 p with 2 remaining flourine .SO B HAS SP3 HYBRIDISATION IN BF3 .

NH3 HAS SP3 HYBRIDISATION

arun.k.iit

this is a coordinate (dative) bond
in this as both are having 4 atoms around each nucleus & as there no

bonds

BOTH THE ATOMS ARE HAVING sp³

please rate

chimanshu_007

both hav sp3 hybradisation

shine

yaa its sp3 for both of them

iitkgp_bipin

In BF₃ molecule with three bonds to fluorine (sp₂ hybridization), and no lone pairs, there remains one 2p-orbital that is not hybridized and empty. Also, fluorine is highly electronegative, withdrawing electron density from the boron atom.Hence BF₃ is a good acceptor of electrons and therefore a good Lewis acid.

NH₃ has a lone pair of electrons and acts as a lewis base.It donates its lone pair of electrons to BF₃.

This reaction fills BF₃'s empty 2p-orbital, and now boron is sp³ hybridized when previously as BF₃ it was sp² hybridized. NH₃ is also sp³ hybridized.

rajneesh

both have sp3 hybridisation

prkiitman

bth r sp3 hybridised

agnit_thebest

Both have the hybridisation sp3.

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