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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: chemical bonding
Forum Index -> Inorganic Chemistry like the article? email it to a friend.  
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suryatejaa (94)

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if possible can u get me a bit of notes on hybridization plzzzzzzzzzzzzzzzzzzzz rate guarentee
    
chakradarraju (17)

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i am having something in writen form.
Can u wait for it to be in typed form.
i will give u the important point from which u can understand it.


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sumansumitha (30)

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according to the concept of hybridization,certain orbitals of neraly the same energy undergo mixing to produce equal number of new orbitals.The new orbitals formed are called hybrid orbitals.The process of mixing of the atomic orbitals to form new hybrids orbitals are called HYBRIDIZATION........

SOME FEATURES ARE;

1.the no of hybrid orbitals must be equal to the no of atomic orbitals....
2.the hybridized orbitals are always equal in energy and shape.

if it is helpful...........rate me

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varshavallig (798)

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sumansumitha is rite.
some more about hybridisation..........
types:
1)sp               -linear geometry           -co.no=2        eg:C2H2
2)sp2             -trigonal planar              -co.no=3              C2H4
3)sp3,            -tetrahedral                       4                     CH4
dsp2              -square planar                     4                     Ni(CO)4  
4)sp3d            -trigonal bipyramidal           5                       PCl5 
5)d2sp3 or sp3d2     -octahedral                6                      SF6  
 
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chimanshu_007 (11437)

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method for finding hyb.

first calculate all the valence electrons in the comp.
eg. in C02 = 4 + 2*6 = 16
then if it comes b/w 2 to 8 divide it by 2
also if it comes b/w 9 and 56 divide it by 8 and the remainder by 2
add the 2 quotients
if
2 = sp
3 = sp2
4 = sp3
5 = sp3d
6 = sp3d2
7 = sp3d3

eg. in CO2 = 16 ans is 16/8 = 2 so CO2 is sp hyb.

XeF4 = 8 + 4*7 = 36
= 36/8 = 4 +(4 remainder)
divide 4 by 2 = 2
ans is 4 + 2 = 6 so XeF4 is sp3d2 hyb.

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