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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2008 16:47:25 IST
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What is the equivalent weight of CO2 ? (in general) in RC Mukherjee in many question its given by M/2. howz that possible... ex: 2NaHCO3 -------> Na2CO3 + H2O +CO2. heat there's no change in oxidation state of C so the equivalent weight should also be M only....how is M/2 possible.? plz help wid a good xplanation. Rates assured
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PROGRESS ISN'T MADE BY EARLY RISERS OR HARD WORKERS, BUT BY LAZY PEOPLE TRYING TO FIND EASIER WAY TO DO THE SAME.....SO BE LAZZZZYY!!!! |
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equivalent weight depends on reaction to reaction
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3 Mar 2008 17:15:41 IST
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i too know that but i'm asking for the reaction given above...
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PROGRESS ISN'T MADE BY EARLY RISERS OR HARD WORKERS, BUT BY LAZY PEOPLE TRYING TO FIND EASIER WAY TO DO THE SAME.....SO BE LAZZZZYY!!!! |
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3 Mar 2008 17:33:55 IST
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edited
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3 Mar 2008 17:41:41 IST
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no dude this isn't the answer.... any1 plz....
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PROGRESS ISN'T MADE BY EARLY RISERS OR HARD WORKERS, BUT BY LAZY PEOPLE TRYING TO FIND EASIER WAY TO DO THE SAME.....SO BE LAZZZZYY!!!! |
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3 Mar 2008 17:45:45 IST
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ohk dude..cud u giv me the question here?.. associated with this question?..may b that cud help..me...and others,,in solvin the issue
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3 Mar 2008 17:48:14 IST
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Pg 122... Ex. 36
last step on the page
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PROGRESS ISN'T MADE BY EARLY RISERS OR HARD WORKERS, BUT BY LAZY PEOPLE TRYING TO FIND EASIER WAY TO DO THE SAME.....SO BE LAZZZZYY!!!! |
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3 Mar 2008 17:51:00 IST
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sorry..i din mean the page num and q no..i dont hv this book..
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3 Mar 2008 17:55:25 IST
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Q. 2g of mixture of carbonate, bicarbonate and chloride of Na, on heating produce 56 mL of CO2 at NTP. 1.6g of the same mixture required 25mL of N HCl solution 4 neutralization . Calculate the %age of Na2CO3, NaHCO3 and NaCl in the mixture from the above given data.
Ans.
On heating the mixture, only NaHCO3 decmposes as
2NaHCO3 -------> Na2CO3 + H2O +CO2.
heat
therfore equivalent of NaHCO3 = Eq. of CO2 = 56/11200
(1 Eq. of CO2 occupies 11200 mL at NTP)
CAN ANY1 EXPLAIN THE LAST 2 Steps of the ANSWR......
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3 Mar 2008 18:05:33 IST
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i think the neutralization here is done by sodium carbonate...
so the reaction shud be
2HCl + Na2CO3 ----> 2NaCl + H2CO3
here.. 1 mole HCL needs just Half a Mole Na2CO3.. so while prodicng half a mole na2co3..half a mole co2 is produced..as per the equation u gave...
thats y on neutralization of 1 equivalent HCL only half a mole of CO2 is produced...that means its equivlent is M/2
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3 Mar 2008 18:09:47 IST
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i would say that since valency of C does not change in this reaction, so it is not a redox reaction.(hence we would take the normal equivalent weight of CO2 which is found through---
equivalent weight of CO2 can be found through this reaction
C02 + H20 ->H2CO3
here we can easily see that eq weight of CO2 is M/2
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Impossible To be Impossible is Impossible |
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3 Mar 2008 18:21:32 IST
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in the reaction
CO2 + H20 -> H2CO3
1 mole of CO2 reacts with 1 mole of H2CO3
or
1 mole of CO2 reacts with 2 equivalents of H2CO3 (dibasic acid)
or
1/2 mole of CO2 reacts with 1 equivalent of H2CO3
hence
eq weight of CO2 is M/2
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Impossible To be Impossible is Impossible |
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3 Mar 2008 18:22:50 IST
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@ anchit
is there anythin wrong with the concept i used above?.. jus to clarify...
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3 Mar 2008 18:23:45 IST
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@ashwin4u4ever
dude i know the soln...but i'm askin 4 xplanation of the last 2 steps i wrote in my answer.
anywyz thanks 4 tryin...
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PROGRESS ISN'T MADE BY EARLY RISERS OR HARD WORKERS, BUT BY LAZY PEOPLE TRYING TO FIND EASIER WAY TO DO THE SAME.....SO BE LAZZZZYY!!!! |
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3 Mar 2008 18:25:02 IST
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