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Inorganic Chemistry
27 Mar 2007 11:18:04 IST
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15
2080
formulas again!!!!!!!!!!
None
Chemical tests to dist. b/w gases
1)CO2
.... turns lime water milky
Ca (OH)2 + C02
CaCO3 + H2O
CaCO3 + H2OBUT MILINESS DISAPPEARS AFTER SOMETIME if CO2 IS TAKEN IN EXCESS
CaCO3 + H2O + CO2-----> Ca (HCO3)2
2) H2S
rotten eggs like smell
turns moist lead acetate ppr black
(CH3COO)2Pb + H2S -----> PbS + 2 CH3COOH
Comments (15)
goutham harsha (1nkZ)
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Joined: 7 Feb 2007
Posts: 544
27 Mar 2007 14:34:41 IST
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Hi Himanshu......m presenting a few points which i know...evry one, hope this is useful...
CO2 when passed in lime water forms a white turbidity?.when excess gas is passed, then solution becomes clear..
CO2+ Ca(OH)2 -> CaCO3 + H2O
CO2 when passed in baryta solution, a white ppt is formed..on excess passing, it turns clear..
CO2+Ba(OH)2 -> BaCO3 + H2O
Carbonates of all alkali metals are stable towards heat except Li2CO3
Silver carbonates and other oxy salts of silver on strong heating form silver metal.Same is the case with mercury.This is possible for none others..
Tests for SO2:
1) acidic K2Cr2O7 is turned green
2) Colour of acidic KMnO4 solution is discharged
3) Colour of iodine soln is discharged
4) Acidic KIO3/ starch paper is turned blue
5) When passed in lime water, a white turbidity is formed and when excess gas is passed, a clear solution is formed.
All +3 state chromium salts are green in colour....
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27 Mar 2007 14:48:47 IST
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NO2
rededish brown gas
suffocating smell
turns FeSO4 sol brownish black
FeSO4 + NO2 + H2SO4 ------->Fe(SO4)3 + H2O + NO
NH3
COLOURLESS GAS WID AMMONICAL SMELL
TURNS NESSLER'S REAGENT (k2HgI4) REDDISH BROWN
K2HgI4 + KOH + NH3 -----> NH2HgO.HgI (MILLON'S BASE) +KI +H2O
27 Mar 2007 15:15:42 IST
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Tests for H2S:
1) colour of acidic K2Cr2O7 changes to green and yellowish white ppt is formed
2) colour of acidic KMnO4 is discharged and yellowish white ppt is formed
3) colour of iodine solution is discharged and yellowish white ppt is formed
I2 + H2S -> 2HI + S colloidal sulphur is formed.
4) lead acetate paper is turned black
H2S + (CH3COO)2Pb -> PbS + 2CH3COOH
5) cadmium acetate paper is turned yellow
H2S + (CH3COO)2Cd -> CdS + 2CH3COOH
27 Mar 2007 16:17:03 IST
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Q1- In a saturated solution of AgCN, if HCN gas is passed, what will be the impact on ionisation of AgCN and its precipitation?
A1- CN- ion is common ion for both AgCN and NaCN. In a saturated solution of AgCN, equilibrium exists. As common ion is present, reaction shifts to the left i.e precipitation of AgCN occurs due to presence of common ion.
AgCN <--> Ag+ + CN-
HCN <--> H+ + CN-
hey good job done kghedrui and chimanshu.
people common, add to this.
15 Oct 2007 23:22:09 IST
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test for nitrates:(NO3- )
1)when salt is heated with copper turnings only brown gas N02 is evolved.
when passed through neutral ferric chloride turns the soln. brownish black
2)Brown Ring Test : Nitric acid is produced at the interface between the nitrate solution and the conc sulphuric acid. The nitric acid is reduced to nitrogen monoxide by the iron(II) ions and the brownish violet nitroso complex is then formed by nitrogen monoxide with the excess iron(II) ions.
3)diphenyl amine when added to aq. soln of salt blue solution obtained
diphenyl amine or Phenylbenzenamine is an aromatic amine with the structural formula (C6H5)2NH
1)when salt is heated with copper turnings only brown gas N02 is evolved.
when passed through neutral ferric chloride turns the soln. brownish black
2)Brown Ring Test : Nitric acid is produced at the interface between the nitrate solution and the conc sulphuric acid. The nitric acid is reduced to nitrogen monoxide by the iron(II) ions and the brownish violet nitroso complex is then formed by nitrogen monoxide with the excess iron(II) ions.
6 FeSO4 + 2 HNO3 + 3 H2SO4 ? 3 Fe2(SO4)3 + 2 NO + 4 H2O
[Fe(H2O)6]SO4 + NO ? [Fe(H2O)5NO]SO4 + H2O
[Fe(H2O)6]SO4 + NO ? [Fe(H2O)5NO]SO4 + H2O
3)diphenyl amine when added to aq. soln of salt blue solution obtained
diphenyl amine or Phenylbenzenamine is an aromatic amine with the structural formula (C6H5)2NH
14 Dec 2007 15:39:52 IST
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Imp points-
(1)Green Vitral is only compound which gives 2 oxides of Sulphur on heating.
FeSO4.7H2O------> Fe2O3+SO2+SO3
(2)All NH4+ salts on reacting with NaOH or KOH evolve NH3 gas.
(3) Al,Sn,Zn,Pb,Cr-Their hydroxides(formed by reacting them with NaOH) are soluble in NaOH and their ppt are white in colour(except Cr which is green).
(4)In the whole salt analysis, buff colour comes only at 2 places-
With Mn and in the complex of Co with CN- Co(CN)2
(5) CoS,NiS,HgS are soluble only in aqua regia(AgNO3+HCl)
(1)Green Vitral is only compound which gives 2 oxides of Sulphur on heating.
FeSO4.7H2O------> Fe2O3+SO2+SO3
(2)All NH4+ salts on reacting with NaOH or KOH evolve NH3 gas.
(3) Al,Sn,Zn,Pb,Cr-Their hydroxides(formed by reacting them with NaOH) are soluble in NaOH and their ppt are white in colour(except Cr which is green).
(4)In the whole salt analysis, buff colour comes only at 2 places-
With Mn and in the complex of Co with CN- Co(CN)2
(5) CoS,NiS,HgS are soluble only in aqua regia(AgNO3+HCl)
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