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Inorganic Chemistry

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28 Jan 2009 05:52:46 IST

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geomitric shape of XeF4

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geomitric shape of XeF4

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rtrikha

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28 Jan 2009 06:35:57 IST

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THE shape is square planar due to the presence of TWO lone pairs of electrons (VSEPR THEORY)

saharsha kumar keshkar

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28 Jan 2009 09:57:36 IST

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10904him

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28 Jan 2009 10:25:44 IST

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XeF4------Xe has 8 e-----4 are used in 4bond pairs----rest form 2 lone pairs----6 pairs-----sp3d2-------for min repulsions 2e- lone pairs align opposite to each other axially-----F occupy eqt positions

-------shape is square planar

-----but geometry is octahedral.

-->Remember geometry and shape are two different things but well correlated---you just need not take lone pairs into account for shape of molecule.

Anshu Sharma

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28 Jan 2009 10:31:01 IST

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first u find the no of valence electrons in Xe and then u find it in Xe⁺² excited state. then u show the hybridisation of shells and then the bond between Xe and F thus forming an sp³d² complex and having square planar shape coz the 2 lone pairs destort its geometry of octahedral structure.

JPS

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28 Jan 2009 12:09:38 IST

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square planar.

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