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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 13:59:39 IST
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what is order of size of cation for Na+.Li+,Al3+,Be2+
how do u determine size of cation is large r less than other??
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15 Mar 2008 14:15:14 IST
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is the answer Na+ > Al3+ > Li+ > Be2+ ?
for isoelectronic species, the more positive atom has radius lesser than the others
here Na+ and Al3+ are isoelectronic and Li+ and Be2+ are isoelectronic
so, their sizes are in the order Na+ > Al3+ and Li+ > Be2+
and Al3+ has one shell more than Li+ and so its size is bigger than Li+
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For the species having equal no. of e- then one which is experiencing more effective nuclear charge have less or shorter radius .hence answer is
Na+>Al3+>li+>Be2+
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15 Mar 2008 17:55:34 IST
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Be has 4 elctrons n 4 protons thus removin 2 e d enc will b by 4protons n it will b faced by 2 elctrons whereas in Li it has 3 elctrons n 3 protons thus removin one elctron enc will b by 3 protons thus enc of be will b >>> then enc of li thus order is Na+ > Al3+ > Li+ > Be2+ ? m i rite ??
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15 Mar 2008 17:56:38 IST
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correct your answer Ankur....
Na+>Al3+>Li+ >Be2+......
your reason is abs correct....
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16 Mar 2008 23:34:12 IST
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ankur is correct.
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23 Mar 2008 10:32:57 IST
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first of all we know that size of atom atom increases down the group and decreases from left to right in a period .......ok ...so regarding Na+ and Li+.....size of Na+ > Li+ as size of Na > Li so their cations will decrease in size in same ratio as both r losing the same no. of e-......Now for Be+2 and Al+3...same explanation.... size of Be > Al (bcoz size of atom decreases from left to right in a period) even Al+3 possess more +ve charge so it has lost more e- compared to other atoms .......hence finally the order is..... Al+3 < Be+2 < Li+ < Na+ its what i feel...well i think my explanation is correct....
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23 Mar 2008 11:02:41 IST
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Yeah i also think that the correct order is :- Na+ > Al3+ > Li+ > Be2+
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24 Mar 2008 09:42:55 IST
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first of all we know that size of atom atom increases down the group and decreases from left to right in a period .......ok ...so regarding Na+ and Li+.....size of Na+ > Li+ as size of Na > Li so their cations will decrease in size in same ratio as both r losing the same no. of e-......Now for Be+2 and Al+3...same explanation.... size of Be > Al (bcoz size of atom decreases from left to right in a period) even Al+3 possess more +ve charge so it has lost more e- compared to other atoms but Al3+ comes in the 3rd period and Be2+ comes in the 2nd oeriod so comparably it is correct and obvious that Na+>Al3+>Li+>Be2+ am i rite???
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