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Inorganic Chemistry
This a very good and conceptual question,most books get it the wrong way.I know the answer but still liked it too share with you all.The second line is hint .
Q) XeO4 is a compound of Xe and O. Explain the geometry and hybridisation of the molecule.
The structure should also account for the fact that XeO4 is very explosive in nature.
Comments (10)
but in physical chem forum, i already answered it. u shud tell me y i m wrong......n i think i answered d correct ans....krishna.gopal sir also answered d same....u cn see in d link below-http://www.goiit.com/posts/list/physical-chemistry-xeo4-81151.htm
if u hv found some other ans, tell us,whether its str is not tetrahedral or its hybridization is not sp3!!!!
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its hybridization is sp3 i.e. its structure is tetrahedral. dis is b'coz xe binds to oxigen by 2 bonds one of vich is pi n d other is sigma bond. since hybridization always explains d 4mation of sigma bonds,so here we only consider sigma bonds in finding its hybridization as well as structure. xe hs 8 electrons in its valence shell n it also hs vacant d orbital. therefore by exiting it, 4 electrons of xe r sent to its vacant d orbital n d rest 4 electrons r remain in s and p orbitals.thus 1 s orbital n 3 p orbitals forms 4 new hybrid orbitals of equal energy. d 4 electrons in d orbitals r involved in pi bond formation. as its hybridization state is sp3, so its structure is tetrahedral.
correct me if m wrong............