let the ml requored be x and y respectively
n1 v1 +n2 v2 = N V
n1=12 n2 =3 v1 =x v2 =y N=6 V=1
12x +3y =6 ---------------------------------------------------------------------------------------------------1
also since both the solutions are of hcl, intial volume = final volume
initial vol =x+y
final volume =1 therefore x+y =1-------------------------------------------------------------------------2
from 1 and 2
x = 1/3 =0.333 and y= 2/3 = 0.667
let the ml requored be x and y respectively
n1 v1 +n2 v2 = N V
n1=12 n2 =3 v1 =x v2 =y N=6 V=1
12x +3y =6 ---------------------------------------------------------------------------------------------------1
also since both the solutions are of hcl, intial volume = final volume
initial vol =x+y
final volume =1 therefore x+y =1-------------------------------------------------------------------------2
from 1 and 2
x = 1/3 =0.333 and y= 2/3 = 0.667