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Inorganic Chemistry
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29 Jan 2012 19:54:03 IST
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It's a transition where an electron jumps from one d orbital to another. Normally these are degenerate (the d orbitals have the same energy), but under some conditions, such as the presense of ligands, the degeneracy can be removed so that there is a specific energy (and therefore wavelength) associated with these transitions.
These sorts of transitions sometimes have energies located in the visible band, and it's one reason transition metal ions (and complex ions in particular) tend to be highly colored.












Hello dear!!!!!!!
I guess you are familiar with the fact how the d-orbitals are oriented on the plane...
dxy,dyz,dxz these are oriented along the line .....symmetrically at angle 45 degree between the axis....refer to the figure::::
Also the orbital dx^2-y^2 and dz^2........both are along the x-axis...
A ligand always approach towards the central atom along the axis....it means these two orbital will have more repulsion as compared to the other three{dxy,dyz.dxz}.........means ofcourse dz^2 and dx^2-y^2 has higher energy....
These two orbitals are splitted and form another energy level....above than the energy level of the other three obitals....
Now when electron from the higher energy orbital...{dz^2 and dx^2-y^2}..........jumps to the orbital...dxy ,dyz,dxz....then they realese energy.......which if falls in visible range....then we see colours in the crystal......
these transition of electron from one orbital of d to another is called d-d transition..