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Inorganic Chemistry
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order of 1st ionisation energy is o^2+>o^2>o^2-
this is surely correct because in case of o^2+ the no of electrons in valence shell decreases so size also decreases resulting in increasing the force of attraction which leads to inc the IE
while in o^2- the no of valence electrons in the outermost shell inc result in inc the size which leads to inc the repultion between elect than attraction so IE is low
as IE is the energy req to remove an elect so it is easy or less energy req to remove elect from outermost shell
i hope u will satisfied
so rate me
d order given by d second person is rite
itz O2+>O2>O2-
coz in O2 + d elctrons no is less then d protons thus d net force of attraction is more( hope ya knw slater's rule)
thus itz difficult 2 remove elctrons
wer as in O2- d elctrons r very loosely bound thus can b removed easily













O2+> O2-> O2
because you are removing electrons from the bonding MO in the first case, fully filled antibonding MO in the second case and half filled antibonding MO in the third case.
hope that answers ur question.
pls correct me if wrong