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x3e belongs to the noble gas family so have 8 valence electron..........xe=5s(2)5p(6)..........2 of theseare bonded with flourine..............this you areleftwith 3 lone pairs...........so hybridisation is sp(3)d.........so shaoe is trigonal bipyradimal.............but you have 3 lone pairson equitorial plains &2 bond pairson axial.......so final shape is linear........
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When you draw out the Lewis structure for XeF2, with Xe having three lone pairs and two bonds with each F, with a total steric number of 5. This also means that there are five orbitals present. The only possible hybridization with five orbitals is dsp3 hybridization. (1d+1s+3p=5dsp3)
If you think in terms of VSEPR geometry, XeF2 has a trigonal bipyramidal design. Trigonal Bipyramidals have dsp3 hybridization.