Integral Calculus

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28 Mar 2012 22:53:07 IST
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definite integrals
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Integral Calculus

 integration of [2/e^x] limits 0 to infinity and  [.] represents greatest integer function.

 

Ans. given ln2



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Blazing goIITian

Joined: 21 Mar 2012
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28 Mar 2012 23:06:17 IST
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first change the limits i.e. form infinity to zero by putting -ve singn ahead noowwww.........brek it in infinity to ln2 which will be zero and with it also with limit ln2 to o which will be 1 only remaining is intregration of dx from ln2 to 0 so we get -ln2 and by -ve sign we get earlier by untechanging the limts answer will be ln2 as given by u and i solve it


Blazing goIITian

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28 Mar 2012 23:08:26 IST
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here i break it in infinity to ln2 bcoz e^ln2 = 2 and 2/2=1 with e^-infinity=0 so gertest integer value in range 0 to 1 will be zero

Blazing goIITian

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28 Mar 2012 23:09:13 IST
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plllllllllllllllllllzzzzzzzzzzzzzz hit like if u find it helpfull since i help u now u should help me by clcking like
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Scorching goIITian

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28 Mar 2012 23:25:36 IST
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explain tarun....

Blazing goIITian

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28 Mar 2012 23:27:58 IST
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i had done so in first comment

New kid on the Block

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29 Mar 2012 23:16:56 IST
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 thank you..


Blazing goIITian

Joined: 21 Mar 2012
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29 Mar 2012 23:22:22 IST
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no thnk needed only give like to all my post right there then u thank u



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