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Integral Calculus
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given Eqn :: y = ( C1 + C2) cos ( x + C3) + C4 e^ ( x + C5 )
y = ( C1 + C2) cos ( x + C3) + C4 (e^ x * e ^ C5 )
y = A cos ( x + B ) + C4 * e^ C5 * e^x
so,
y = A cos ( x + B ) + C * e^x
wer A, B, C are constants { A = C1 + C2 , B = c3 and C = c4 * e ^ C5 }
so, there are 3 constants
hence, order = 3
y = ( C1 + C2) cos ( x + C3) + C4 e^ ( x + C5 )
dy / dx = - ( C1 + C2) sin ( x + C3) + C4 e^ ( x + C5 )
d2y / dx2 = - ( C1 + C2) cos ( x + C3) + C4 e^ ( x + C5 )
d3y / dx3 = ( C1 + C2) sin ( x + C3) + C4 e^ ( x + C5 )
now ,
d3y / dx3 + d2y / dx2 - ( dy / dx + y) = 0
or,
d3y / dx3 + d2y / dx2 - dy / dx - y = 0
this is a differantial equation in x whose order is 3 and degree 1
hope you got now~
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