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Integral Calculus

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28 Mar 2009 12:28:18 IST

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good question ..rates assured

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Lim(xà0) (1/x){∫e^((sint)^2)dt- ∫e^((sint)^2)dt} is eql to.

first integration limit(lower = y ,upper =a)

second integration limit ( lower = x+y upper =a)

{kindly write the question in proper way...i m unable write here in proper way.}

a)e^((siny)^2)

b)0

c)1

d)none of these...

reply soon..rates assured

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Comments (10)

ar rehman

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Joined: 24 Feb 2009

Posts: 119

28 Mar 2009 12:31:17 IST

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its not clear..it is

limx-->0

solve karo! please

prahalad agarwal

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Posts: 128

28 Mar 2009 12:31:27 IST

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Be specific and clear ...we cant give u an answer for a question which is to be guessed

ar rehman

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Posts: 119

28 Mar 2009 12:34:25 IST

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it is clearly visible...just try yaar...dont give such comments...presently i m unable to write in proper way..

saharsha kumar keshkar

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Joined: 7 Aug 2008

Posts: 1104

28 Mar 2009 12:45:25 IST

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is this is ur questionnnnnn?

reply soon and make correction

AND ALWAYS WRITE IN PROPER WAYS>>>>

ar rehman

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Joined: 24 Feb 2009

Posts: 119

28 Mar 2009 12:48:18 IST

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no in my ques -ve sign is between two integrations functions....

saharsha kumar keshkar

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Posts: 1104

28 Mar 2009 12:50:46 IST

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aree! tik is dekho.....maine tumhare ques ko little bit in different form..

as this is the first step of my solution...

i.e. reversing limit leads to change in sign....

go to properties......

i m solvin rest part...soon.

ar rehman

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Joined: 24 Feb 2009

Posts: 119

28 Mar 2009 12:52:28 IST

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ya! correct..sorry.

solve soon...i m waitin....

answer given is (a).

saharsha kumar keshkar

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Joined: 7 Aug 2008

Posts: 1104

28 Mar 2009 13:12:52 IST

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by usein properties of limits i.e... merge into one.

as clearly visible form is 0/0...and gointo use L' hospital rule.....

and getting.......

good ques...

hence the answer is (a)...

any doubt nudge me.....

ar rehman

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Joined: 24 Feb 2009

Posts: 119

28 Mar 2009 13:16:14 IST

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thanx brother...........deserves rates....

rakesh verma

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Joined: 24 Mar 2009

Posts: 12

28 Mar 2009 13:36:56 IST

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good ques and good solution

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