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Integral Calculus
ar rehman's Avatar
ar rehman
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28 Mar 2009 12:28:18 IST
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good question ..rates assured
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Integral Calculus

Lim(xà0)   (1/x){∫e^((sint)^2)dt- ∫e^((sint)^2)dt} is eql to.

first integration limit(lower = y ,upper =a)

second integration limit ( lower = x+y upper =a)

{kindly write the question in proper way...i m unable write here in proper way.}

a)e^((siny)^2)

b)0

c)1

d)none of these...

reply soon..rates assured


Comments (10)

ar rehman's Avatar

ar rehman
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28 Mar 2009 12:31:17 IST
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its not clear..it is

limx-->0

solve karo! please
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prahalad agarwal's Avatar

prahalad agarwal
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28 Mar 2009 12:31:27 IST
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Be specific and clear ...we cant give u an answer for a question which is to be guessed
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ar rehman's Avatar

ar rehman
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28 Mar 2009 12:34:25 IST
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it is clearly visible...just try yaar...dont give such comments...presently i m unable to write in proper way..
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saharsha kumar keshkar's Avatar

saharsha kumar keshkar
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28 Mar 2009 12:45:25 IST
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is this is ur questionnnnnn?

reply soon and make correction

AND ALWAYS WRITE IN PROPER WAYS>>>>
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ar rehman's Avatar

ar rehman
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28 Mar 2009 12:48:18 IST
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no in my ques -ve sign is between two integrations functions....
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saharsha kumar keshkar's Avatar

saharsha kumar keshkar
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28 Mar 2009 12:50:46 IST
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aree! tik is dekho.....maine tumhare ques ko little bit in different form..

as this is the first step of my solution...

i.e. reversing limit  leads to change in sign....

go to properties......

i m solvin rest part...soon.
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ar rehman's Avatar

ar rehman
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28 Mar 2009 12:52:28 IST
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ya! correct..sorry.

solve soon...i m waitin....

answer given is (a).
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saharsha kumar keshkar's Avatar

saharsha kumar keshkar
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28 Mar 2009 13:12:52 IST
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by usein properties of limits i.e... merge into one.

as clearly visible form is 0/0...and gointo use L' hospital rule.....

and getting.......

good ques...

hence the answer is (a)...

any doubt nudge me.....
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ar rehman's Avatar

ar rehman
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28 Mar 2009 13:16:14 IST
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thanx brother...........deserves rates....
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rakesh verma
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Joined: 24 Mar 2009
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28 Mar 2009 13:36:56 IST
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good ques and good solution
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