
This is the graph of |x| + |y| = 1.
So, area within the curve = area of square ABCD = 2 sq. units.
or, by integration,
area within the curve = 4 times area of triangle AOB = 4 int x from 0 to 1 (1 - x).dx = 4(x - (x2/2)) with limit of x from 0 to 1
= 4(1 - (1/2)) = 4(1/2) = 2 sq. units.
How to draw the graph
|x| + |y| = 1
For x,y>0; eq. is x + y = 1
For x>0 and y<0; eq. is x - y =1
For x<0 and y>0; eq. is - x + y =1
For x,y<0; eq. is - x - y = 1
This is the graph of |x| + |y| = 1.
So, area within the curve = area of square ABCD = 2 sq. units.
or, by integration,
area within the curve = 4 times area of triangle AOB = 4 int x from 0 to 1 (1 - x).dx = 4(x - (x2/2)) with limit of x from 0 to 1
= 4(1 - (1/2)) = 4(1/2) = 2 sq. units.
How to draw the graph
|x| + |y| = 1
For x,y>0; eq. is x + y = 1
For x>0 and y<0; eq. is x - y =1
For x<0 and y>0; eq. is - x + y =1
For x,y<0; eq. is - x - y = 1