|
Author
|
Message
|
10 Mar 2009 21:05:34 IST
|
|
|
IIT BOMBAY OLYMPIAD QUESTION INTEGRATION SOLVE THIS !!integral-((pi/2)(0)[log(tanx)])
|
|
|
|
10 Mar 2009 21:23:52 IST
|
|
|
I= int ( pi/2 , 0 ) log(tan(x)) dx I= int (pi/2 , 0) log(cos(x)) dx Adding above 2I= int (pi/2 , 0) log (1) dx I= 0 thank u
|
The time u guys take to find the derivative of a function or for finding the equilibrium constant of a reaction or for finding the angle of dispersion of prism or for standing from ur seat to congratulate our team after their win almost in that time one kid die because of poverty. |
this reply:
5 points
(with 1

in
1
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 00:21:11 IST
|
|
|
are you sure ??? Coz doesnt definite integral gives area under curve here we have logtanx tanx-->inf. to pi/2 the are i can t think can be zero .
|
this reply:
5 points
(with 1

in
1
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 15:26:05 IST
|
|
|
definite integral gives area under the curve but doesn't take into account the sign....so the area can come 0 or negative........
|
this reply:
0 points
(with 0

in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 15:27:58 IST
|
|
|
yeah ... so probably below the point x = pi/4 where y = 0 ..... area is negative and its magnitude equals d area of d part above d x-axis .....
|
-na- |
this reply:
0 points
(with 0

in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 20:24:28 IST
|
|
|

|
The time u guys take to find the derivative of a function or for finding the equilibrium constant of a reaction or for finding the angle of dispersion of prism or for standing from ur seat to congratulate our team after their win almost in that time one kid die because of poverty. |
this reply:
5 points
(with 1

in
1
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 20:25:51 IST
|
|
|
so here is graphical solution .Man.
|
this reply:
10 points
(with 2

in
2
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 20:52:56 IST
|
|
|
amazing....
|
There's a concept that works,
half a million aspirants emerge...
But no matter how many ** in the zoo,
It'll be so empty without you... |
this reply:
0 points
(with 0

in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 21:17:07 IST
|
|
|
its not amazing.ya u can say my calculator is amazing who made it in splits of second.
|
this reply:
5 points
(with 1

in
1
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 21:19:32 IST
|
|
|
not the graph...ur efforts to help ...
|
There's a concept that works,
half a million aspirants emerge...
But no matter how many ** in the zoo,
It'll be so empty without you... |
this reply:
0 points
(with 0

in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
11 Mar 2009 21:20:50 IST
|
|
|
graph toh koi bhi daal sakta hai ....net se ...calculators se ...aur ...etc etc....
|
There's a concept that works,
half a million aspirants emerge...
But no matter how many ** in the zoo,
It'll be so empty without you... |
this reply:
0 points
(with 0

in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
|
|