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Integral Calculus
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2 Dec 2009 13:04:27 IST
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2 nd method This way is my way to solve this
look
(x sin(x)+cos(x) ) = Sqrt(1 +x2 ) cos( x -tan-1(x))
so ur question become
int ( x2 sec2 (x -tan-1x ))/(1+x2) dx
put x-tan^(-1)x = t
x2/(1+x2)dx =dt
= int sec^2 t dt
= tan (x -tan-1(x)) +C
thank u













hi
i have 2 method
1st method
I = integration ( x sec(x) x cos(x)/(xsinx +cos(x))2 dx
integration by parts
=x sec(x) int ( xcosx /(xsinx +cos(x))2 dx) - int [ ( xsecxtanx+secx) int (xsinx +cos(x))2 ]dx
= -xsecx / ( xsinx+cosx) + int (sec^2x)dx
= -xsecx / ( xsinx+cosx) +tanx +c
thank u