Home » Ask & Discuss » Mathematics. » Integral Calculus « Back to Discussion

Integral Calculus

Cool goIITian

Joined:	7 May 2009
Post:	51

22 Dec 2009 17:03:05 IST

0 People liked this

586

plz solve these integrals

None

plz solve these integrals

$\int e^{x}\left ( \frac{x^{4}+2}{(1+x^{2})^{5/2}} \right )dx$

$\int log(\sqrt{1+x}+\sqrt{1-x})dx$

Share this article on:

Comments (5)

snehil

Cool goIITian

Joined: 7 May 2009

Posts: 51

22 Dec 2009 17:07:53 IST

Like 0 people liked this

kabi

Blazing goIITian

Joined: 11 Jan 2009

Posts: 575

22 Dec 2009 18:40:38 IST

Like 0 people liked this

http://www.goiit.com/posts/list/integral-calculus-indefinte-integration-reloaded-998418.htm

akki ~~ unlucky forever ~~

Blazing goIITian

Joined: 11 May 2008

Posts: 491

22 Dec 2009 19:12:27 IST

Like 1 people liked this

$I = \int e^x(\frac{x^4+2}{(1+x^2)^\frac{5}{2}})dx\\ \\ \\ now\ in\ such\ questions,try \ to\ arrange\ the\ polynomial\ terms\\ in\ such\ form\ that\ polynomial\ can\ be\ written\ as\ sum\ diff \ of\\ a\ polynomial\ &\ it$

second que is done in link given by Kabi.

The wicked warrior ''Anurag the devil''

Blazing goIITian

Joined: 28 Oct 2009

Posts: 594

23 Dec 2009 16:39:01 IST

Like 0 people liked this

1) take x=tan theta then aplly by parts....quite lengthy but simple ...........................(2)take x=cos 2 theta now..........transform 1-cos 2 theta to 2^1/2 sin^2 theta and 1+ cos 2theta to 2^1/2 sos theta now take log 2^1/2 outside (logmn=logm+logn) and only integration of -log(sin theta + cos theta)sin 2theta remains now use by parts ...................

snehil

Cool goIITian

Joined: 7 May 2009

Posts: 51

24 Dec 2009 13:29:19 IST

Like 0 people liked this

@kabi i din get ur method.....not clear.....and @akki thanks for 1st one and anurag ur method not clear

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team