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Integral Calculus

abhishek's Avatar
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20 Jan 2012 17:51:43 IST
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y=sinx -x find inetgral(-pie to pie)f inverse x
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y=sinx -x find inetgral(-pie to pie)f inverse x


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Vishal U. Karve's Avatar

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20 Jan 2012 18:27:50 IST
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f(x) is odd.

So will f--1(x) be.

An odd function integrated from -pi to pi is zero.

So the answer is zero.

 

Vishal U. Karve's Avatar

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20 Jan 2012 18:32:59 IST
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We cannot expect odd functions to help us all the time so just to be on the safer side, remember

 

abhishek's Avatar

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21 Jan 2012 10:04:33 IST
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 oh man

cosx is an odd function

but is cos inverse isnt

so u r wrong

Vishal U. Karve's Avatar

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21 Jan 2012 10:28:22 IST
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Plz revise your notes...cos x is even and so is its inverse.

abhishek's Avatar

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21 Jan 2012 10:36:04 IST
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 sory but the answer is inst zero

bus is it true always

ex- sin x even but inverse nothing

 

Arjun Virmani's Avatar

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21 Jan 2012 14:27:12 IST
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The formula used is integration by parts:

 intf(x)dx=xf(x)-intf^(-1)(f(x))f^'(x)dx,

as we put limits in it..

                 arrives!!!

In this case it is easy to get a and b for f(a) and f(b) as the limits in the formula to be put are f(a) and f(b) so u'll need a and b for that.........

f(a) = - pi.....

sin a   -   a = - pi.......

a = pi.........!!!

f(b) = pi

sin b  -  b  = pi........

b = pi........!!

now put a and b and find the integral!!!!!




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