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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jul 2007 15:23:43 IST
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Find the area bounded by the curve y=e-x , the X axis and the Y axis.
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jul 2007 16:13:47 IST
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r u sure it meets both the axes ..... please check n reply................
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jul 2007 16:14:02 IST
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The area in the first quadrant of y=e-x is:
The curve touches the axes at 0, .
So, the integral becomes : [0 ] [infinity ] e-xdx = -e-x] from 0 to infinity, substituting the limits, we get the area as 1 unit.
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jul 2007 18:45:21 IST
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The graph of the function e - x is attached with the answer. As, the question wants the area of e - x with X axis and Y axis, it can mean two areas --- the area in the first quadrant and the area in the second quadrant.
Area in the first quadrant = [a ] [ + infinity ] [ 0 ] [a] e - x dx = 1 sq. units.
Area in the second quadrant = [b ] [ - infinity ] [ b] 0[ ] e - x dx =
Remark : Well, obviously, you can conclude from the graph that the area in the 1st quadrant will have finite value as the curve tends to zero as x tends to , and hence tends to a closed bounded figure. On the contrary, the area in the second quadrant has infinite value as the curve tends to as x tends to - and hence has an open unbounded figure.
Hope that satisfies and resolves all query.
Cheers !!!!!
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Titun |
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