find the area included b/w the parabolas  y²=4ax and x²=4by?

answer:(16/3)ab sq. units

that's easy u might b knwin d curves of y^2=x andx^2=y

des curves r of similar type ......so first drw them then  find d point of intersection of d curves

u get y =(4)*(a^2*b)^1/3

ohk ..........nw

integral frm 0 to (4)*(a^2*b)^1/3

solvin u get d answer as 16ab/3 sq units

For standard parabolas whose axis are perpendicular to each other, there is a shortcut of finding the area.

Area is = (Product of their latus rectum) / 3

Here product of latus rectum is 16ab

hence area=16ab/3

rate if useful.