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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: can anyone answer this? plz need fast answer....
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SwiffeR (0)

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thank you in advance.


box x is actually dx

    
paddy.dude (1154)

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is the ans   + 1/2log - 1/ + 1

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paddy.dude (1154)

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  == / x dx


 


now put  X2+1=t2


 


2X dx=2tdt


 


Xdx=tdt


 


x=


 


integral becomes


 


==t/ x t dt/


 


== t2 dt/t2-1


 


== t2+1-1 dt/t2-1


 


== 1 + 1/t2-1


 


the second part is a std integral


 


so we get the ans as




  + 1/2log - 1/ + 1  +






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SwiffeR (0)

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Yes, your answer is correct :)


Thank a lot!

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little_genius (295)

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put x=cot t

integral bcoms

= - sec t * cosec t * cot t dt

= - cosec ^2 t dt

= cot t

=x


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