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Integral Calculus

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2 Jun 2007 10:35:10 IST

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Find the general solution of the differential equation

ylogx.logy.dx+dy=0.

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CyBorG

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Joined: 6 Jan 2007

Posts: 706

2 Jun 2007 11:34:49 IST

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Given ylogxlogydx+dy=0

So ylogxlogy= -dy/dx

or dy/(ylogy)= -dxlogx

Now integrating this we get,

log(logy)= -(xlogx-x)+c

So the general solution is x-xlogx-log(logy)+c=0

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