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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Jan 2008 11:05:40 IST
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evaluate [-1 ] [1 ] sin-1 [x+3/4] where [] denotes the greatest integer fuction
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MONITH BISWOJYOTHI |
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24 Jan 2008 11:24:55 IST
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[-1 ] [1 ] sin -1 [x+3/4] dx = [ -1][ -3/4] sin -1(-1)dx + [-3/4 ][ 1/4] sin -1(0)dx + [1/4 ][1 ] sin -1(1)dx = -  /2 ( -3/4 - (-1)] + 0 + /2 (1-1/4) = - /8 + 3 /8 = /4 |
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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I am only one,
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I cannot do everything,
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25 Jan 2008 07:59:12 IST
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plz explain it man,cant get it
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MONITH BISWOJYOTHI |
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25 Jan 2008 08:13:55 IST
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i think u r clear aftr d 2nd step
For the 2nd step, see:
[x+3/4] will have different integral values in different intervals.
in x= -1 to -3/4, x+3/4 lies btwn -1/4 to 0
so [x+3/4] = -1
In x=-3/4 to 1/4, x+3/4 = [0, 1)
so [x+3/4] = 0
In x = 1/4 to 1, x+3/4 = [1, 7/4)
so [x+3/4] = 1
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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25 Jan 2008 08:19:43 IST
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thats rite,thanx 4 ur help
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MONITH BISWOJYOTHI |
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