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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Feb 2008 22:52:41 IST
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the value of ,0 X [t+1]3dt ([.] denotes greatest integer function)is equal to....
ans
([x]([x]+1)/2)2 + ([x]+1)3{x}
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B.Tech CSE, ISMU |
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12 Feb 2008 23:35:48 IST
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integral
[t+1]cubed
=([t]+1)whole cubed using the fact that
[n+k]=[n]+k where k is a constant
so integral 0to x can be written as o to [x] and
[x] to x
first integral we get 1cube +2 cube+....[x] cubed
using formula it is first part of answer
next one
[x] to x the value of [x]+1 is constant
so that multipled with x-[x]={x}
so thats the answer
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13 Feb 2008 05:37:54 IST
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Well answered @sboosy
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14 Feb 2008 09:52:43 IST
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good answer sobsy...........
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B.Tech CSE, ISMU |
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