IIT JEE , AIEEE Forum - Mathematics , Integral Calculus

tibu

Please solve this one

diff. eqn of (x+y)²=2cx:

(a)y-x=2xdy/dx
(b)x+y=xdy/dx
(c)y=xdy/dx
(d)y-x=2ydy/dx

ruhi

hi there is no ques

tibu

sorry...i put it now.

KAB

The ans is a).

The eqn is {(x+y)^2}/x=2c

Differentiate this wrt x,

2x(x+y)(1+dy/dx)-(x+y)^2=0

or y-x=2xdy/dx

DON007

hey .....look..............

(x+y)²=2cx:..............1

differentiating ......we get.............

2(x+y) ( 1 + dy/dx)= 2c

putting this 2c in equation 1st

we get............

(x+y)²=2cx:

(x+y)²=2 ( x+y) ( 1 + dy/dx) x

cancelling (x+y)................

we get.............

(x+y) = 2x + 2xdy/dx

y-x= 2xdy/dx.......................ans 1....................

right...................

thanku