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Integral Calculus

Blazing goIITian

Joined:	11 Jun 2007
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2 Nov 2007 09:36:39 IST

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537

differential doubt (for iitjee)

None

If y=y(x) and (2+sinx)/(y+1) * dy/dx= - cos x, y(0)=1 then y(pi/2) equals

1/3

2/3

-1/3

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The_Emperor

Blazing goIITian

Joined: 10 Jan 2007

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2 Nov 2007 10:11:42 IST

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ans is 0 yaar

Pratik Anand

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2 Nov 2007 10:18:59 IST

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??????????????? see the options

KAPINJAL CHOWDHURY

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Joined: 30 Oct 2007

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2 Nov 2007 10:28:29 IST

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-1/3

Pratik Anand

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2 Nov 2007 10:33:27 IST

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answer is 1/3. if u solve then psot the solution also.. please

mohd shaheen

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2 Nov 2007 12:19:36 IST

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dy/dx + ycosx/(2+sinx) = -cosx/(2+sinx) .....(1)
P=cosx/2+sinx
e

^{[Pdx ]} =2+sinx .................(2)
Multiply (1) by (2) and find and express y in terms of x
finally put x=

/2 to get answer

mratyudand mratyudand

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2 Nov 2007 16:47:55 IST

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(2+sin x)/(y+1)*dy/dx=-cosx
dy/(y+1)= - cosx dx/(2+sinx)
integratin
ln(y+1)=ln( c/(2+sinx) )

whr c constant of integration

now antilog
y+1=c/(2+sinx).............................(A)
f(0)=1so when x=0 y=1;
now frm (A) c=4
ur function is y+1=4/(2+sinx)
now x=pi/2
y=1/3

siddhant narvekar

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2 Nov 2007 16:58:08 IST

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why is it that aCD when turn over shines and gives a rainbow colour

Pratik Anand

Blazing goIITian

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2 Nov 2007 17:07:22 IST

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yaar siddhant , post ur question in a new topic. this one is already messed up..

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