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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Oct 2007 11:35:34 IST
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dy=(4x+y+1)2 dx
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et 4x+y+1=z diff both sides wrt x 4 +dy/dx =dz/dx dy/dx = dz/dx-4 also dy/dx = z2 so dz/dx - 4 = z^2 or dz/(z2+4) = dx integrt 1/2 tan-1(z^2+4) = x +c put z=4x+y+1 please rate me!
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this reply: 5 points
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2 Oct 2007 11:49:07 IST
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take 4x +y=z dz/dx= 4+dy/dx given eqn becomes.... dz/dx=(z+1)^2+4 dz/(z+1)^2+4=dx integrate 1/2 (tan ^-1(z+1/2))=x+c substitute z by 4x+y rate
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