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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 17:44:53 IST
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solve d3y/dx3+d2y/dx2-2dy/dx=0. give me a proper soln not intuitive guesses like e^x
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 07:04:23 IST
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hmmm is it... y + y^2 / 2 - y^3 / 3 = kx^2 + cx + d
? k, c and d all are constants.
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 12:43:51 IST
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no dude das not the ans.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 13:39:44 IST
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d^3y/dx^3 + d^2y/dx^2 - 2dy/dx = 0
d^3y/dx^3 + d^2y/dx^2 = 2dy/dx
[ d^3y/dx^3 + d^2y/dx^2 ] / 2 = dy/dx
now LHS is average of 2 terms... if RHS is the average of the terms in the numerator of LHS, then it implies from it that : Either ... 1) 1 term is larger than and 1 term is smaller than RHS term by same amount. or 2) both terms are the same in value.
(Example : (3 + 5) / 2 = 4 or (4 + 4) / 2 = 4 )
But (1) cannot b true!!! since derivative of an expression cannot be larger in value than the expression itself.. it is always less than equal to.
Hence we are left with (2) so .... d^3y/dx^3 = d^2y/dx^2 = dy/dx so the value remains the same no matter wat order derivative it is. And only one such expression i know : e^x :)
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---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:08:43 IST
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Spidey, Sorry, but you are completely wrong Who said derivative of a function<the function??????? x^4-1 derivative at x=1 > fn at x=1 so ur line of reasoning is wrong!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:17:15 IST
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hey den can u say wats d ans frnd
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:22:01 IST
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hey elastiboysai is d ans
1/3 y^3 +xy^2 -2xy +c/2x^2 +c1x +c2 =0 is it rite if rite rate me i wud surely giv d ans
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:25:23 IST
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No das not the ans
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:31:27 IST
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EDIT.. we cannot have one derivative being greater than the expression and the next derivative of that as lesser than the expression
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---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:35:31 IST
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tell me d ans my head is bursting
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:38:46 IST
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Aex+Bcos 2 x + Csin 2 x ?
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 14:40:08 IST
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hi buddy i m an eng. stdnt & giving u easy technique 2 solve this ttype of de first consider dy/dx=D,d2y/dx2=D2 and so on now brek the ans. into cf (complimentary function)& pi(particular integral) ci can b cal. as follow 1st form auxillary eqn.like considering dy/dx=m now fctorize the eqn by equating it 2 0 like ur ques m3+m2-2m=0 m(m2+m-2)=0 m=0,1,2 now cf=(constt.1)eox+(constt2)e1x+(consttt.3)e2x so ur ans. is y=cf now try dis mthd 4 anthr de.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 20:00:56 IST
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Sorry... made a mistake...
Ans is A+Bex+C/e2x
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 20:03:56 IST
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Right ans Karthik did u also do it by the method amrish sharma gave ?
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College student da 
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