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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: find the integral
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anpm_dev (111)

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The value of is equal


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allamraju (3437)

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I think the answer is pi/2.



 


Let the given integral be f() then,



 


f'()=(sin2)-(sin2)=0 and hence,the function is a constant.



 


In order to find that constant,let us put =pi/4 for convenience,then,



 





 



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