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Integral Calculus

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16 Nov 2008 00:49:32 IST

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Find the limit: Everyone's invited.

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Evaluate:

$\lim_{n\to\infty}\int_0^\pi \dfrac{\sin x}{1+3\cos^2nx}\ \mathrm{d}x$

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Comments (6)

Anant Kumar

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Joined: 10 Jul 2008

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17 Nov 2008 00:49:29 IST

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someone trying?

Lalit Kumar

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Joined: 13 Nov 2008

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17 Nov 2008 11:36:36 IST

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is it zero?

spiderman

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Joined: 29 Oct 2008

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18 Nov 2008 14:54:48 IST

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sir
please give hint!!!!!!!!!

rohan ghosh

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18 Nov 2008 20:44:35 IST

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well i havent solved it but one thing i got =>

in the denominator replacing cos²nx by 1-sin²nx and multiplying both the num. and den. by sin(nx)

we get =>

(sinx*sin(nx))/sin(3nx))*(-1)

Dipanjan

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21 Nov 2008 23:18:27 IST

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I hope there is no conceptual mistake:

nikhil

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Joined: 5 Oct 2008

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23 Nov 2008 16:40:09 IST

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sir isnt there any another method

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